Howdy, Stranger!
Categories
- All Categories
- 39 Introductions
- 3.6K Typeface Design
- 766 Font Technology
- 1K Technique and Theory
- 590 Type Business
- 435 Type Design Critiques
- 527 Type Design Software
- 30 Punchcutting
- 132 Lettering and Calligraphy
- 79 Technique and Theory
- 53 Lettering Critiques
- 462 Typography
- 289 History of Typography
- 111 Education
- 62 Resources
- 480 Announcements
- 74 Events
- 104 Job Postings
- 147 Type Releases
- 154 Miscellaneous News
- 260 About TypeDrawers
- 52 TypeDrawers Announcements
- 110 Suggestions and Bug Reports
Options
Does one kern a duplex font?
Raphaël Ronot
Posts: 33
Hi, this question hit me the other day. I was wondering if some of you had faced this problem before.
Making a regular and bold weight fit into the exact same width is already difficult, but giving them the same kerning values for every pair seems impossible, right? Take a simple `To` for example. The bolder weight won't allow the `o` to "slide" under the horizontal bar of the `T`.
So what do we do? Should we find an in-between "one size fits all" kerning system that works decently for both masters?
Thanks in advance
Making a regular and bold weight fit into the exact same width is already difficult, but giving them the same kerning values for every pair seems impossible, right? Take a simple `To` for example. The bolder weight won't allow the `o` to "slide" under the horizontal bar of the `T`.
So what do we do? Should we find an in-between "one size fits all" kerning system that works decently for both masters?
Thanks in advance
0
Comments
Identical kerning should be shared among the duplex/multiplex/uniwidth weights. Martin Majoor’s Comma Base and Nick Sherman’s HEX Franklin have identical kerning across their entire weight range, respectively. Matthew Butterick’s Concourse has identical kerning shared within weights 2 (Thin), 3 (Book), 4 (Medium), and 6 (Semibold), furthermore its roman and italic are duplexed and also share identical kerning; though the bolder weights of Concourse break free from this constraint.